WebApr 6, 2024 · To get K elements of the array, print the first K elements of the sorted array. Follow the given steps to solve the problem: Create a map mp, to store key-value pair, i.e. element-frequency pair. Traverse the array from start to end. For every element in the array update mp [array [i]]++ WebJul 21, 2024 · Your task is to find the minimum and maximum elements in the array. Example 1: Input: N = 6 A [] = {3, 2, 1, 56, 10000, 167} Output: min = 1, max = 10000 Example 2: Input: N = 5 A [] = {1, 345,...
First element occurring K times in the array using hashing
WebNov 21, 2024 · If K is the maximum element in the array, then the elements before K in the array should be in the ascending order and the elements after K in the array should be in the descending order. Examples: Input: arr [] = {1, 2, 3} Output: 4 Explanation: There are a total of 6 permutations for the given array {1, 2, 3}. They are: WebDec 7, 2024 · PROGRAM TO PRINT THE FIRST ELEMENT OCCURRING K TIMES IN AN ARRAY import java.util.HashMap; class MAIN { static int firstElement (int arr [], int n, int k) { HashMap count_map = new HashMap<> (); for (int i = 0; i < n; i++) { int a = 0; if(count_map.get (arr [i])!=null) { a = count_map.get (arr [i]); } count_map.put (arr [i], … learning on main aiken sc
algorithm - How do I find elements that are appear k …
WebApr 6, 2024 · Explanation: In the given array arr [], the element that occurs at least M number of times are {2, 3}. Input: arr [] = { 1, 32, 2, 1, 33, 5, 1, 5 }, M = 2. Output: 1 5. Naive Approach: The simplest approach to solve the problem is as follows: Traverse the array from left to right. Check if an element has already appeared in the earlier ... WebFirst element occurring k times in an array: Amazon Hike PayU SAP Labs Teradata Wipro Yatra Zoho hashing: Easy: Maximum product of an increasing subsequence: Accolite GE Healthcare HackerRank IBM Snapchat Yahoo dynamic-programming: Hard: Print all subarrays with 0 sum WebMar 11, 2024 · Method 1: Approach: The basic solution is to have two loops and keep track of the maximum count for all different elements. If maximum count becomes greater than n/3 then print it. If the maximum count doesn’t become more than n/3 after the traversal of array then the majority element doesn’t exists. C++. auto kaufen online