In a trapezium abcd if ab cd then ac2 + bd2
WebRight Answer is: SOLUTION ANSWER: (c) BC2+AD2+2AB.CD Explanation: Draw perpendicular from D and C on AB which meets AB at E and F, respectively. ∴ DEFC is a … WebIn the given figure, if ABCD is a trapezium in which AB CD EF, then AE:ED
In a trapezium abcd if ab cd then ac2 + bd2
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WebSolution Given, quadrilateral ABCD, in which ∠A+∠D= 90∘ To prove : AC2+BD2 = AD2+BC2 Construction : Produce AB and CD to meet at E. Also, join AC and BD. Proof : In ΔAED, ∠A+∠D= 90∘ [given] ∴ ∠E= 180∘−(∠A+∠D) = 90∘ [because sum of all angles in a triangle= 180∘] Then, by using Pythagoras theorem, AD2 = AE2+DE2 ..(i) I n ΔBEC, WebProve that : AB^2 + CD^2 = AC^2 + BD^2. Solve Study Textbooks Guides. Join / Login >> Class 7 >> Maths >> The Triangle and Its Properties >> Right Angled Triangles and ... If A D is perpendicular to B C, then find the length of A B. Medium. View solution > View more. More From Chapter. The Triangle and Its Properties. View chapter > Practice ...
WebDec 12, 2024 · The length of the parallel sides of a trapezium are 14 cm and 7 cm. If the length of third side is 8 cm and of fourth side is x cm , then the number of possible integral values of x are 12
Web1. In a trapezium ABCD, if AB CD, then AC2 + BD2 is equal to: 1. BC2 + AD2 + 2AB. CD 2. AB2 + CD2 + 2AD. BC 3. AB2 + CD2 + 2AB. CD 4. Insufficient data Answer & Solution … WebZA + = LB + ZC = 1800 U Perimeter of Trapezium = a + b *Q-t Area of trapezium =- (AB + CD) x h Diagonal AC BD Diagonal do not bisect each AOAB AOCD OA x OD = 0B x OC U/ AOCD : AOAB = : AB2 AC2+ BD2= AD2+ Bc2+2 X AB X CD D Line formed by joining mid- points of non-parallel sides of a trapezium is half of the sum of its parallel sides.
WebFeb 19, 2012 · In a trapezium ABCD , if AB ll CD , then (AC2 - BD2 )= (i) BC2 + AD2 + 2BC x AD (ii) AB2 + CD2 + 2AB x BC (iii) AB2 + CD2 + 2AD x BC (iv) BC2 + AD2 + 2AB x CD - …
WebDec 12, 2024 · Solution For EXAMPLE 35 In a trapezium ABCD, if AB∥CD, then AC2+BD2= EXAMPLE 35 In a trapezium ABCD, if AB∥CD, then AC2+BD2= Filo The world’s only live … portland or volunteer opportunitiesWebArea of a Trapezium, A = h (a+b)/2 square units. Substitute the given values, A = (60/2)× 20 A = 30 × 20 A = 600 cm 2. Therefore, the area of trapezium = 600 cm 2. Q.2: Find the perimeter of a trapezium whose sides are 3cm, 4cm, 5cm and 6cm. Solution: By the formula of the perimeter of trapezium, we know; P = Sum of all the sides P = 3+4+5+6 optimal setup portable air conditionerWebIn a trapezium ABCD, if AB CD, then prove that AC²+BC²=BC²+AD²+2AB*CD? I previously showed in my answer to the original question below that for an isosceles trapezium, AC^2 … optimal sets per workoutWebABCD is a rhombus AC and BD are diagonals. They bisect perpendicularly at O. ∴AO= 21AC and BO= 21BD In right angled AOB,A O^B=90 o According to Pythagoras theorem, we have AB 2=AO 2+BO 2 =(21AC)2+(21BD)2 = 41AC 2+ 41BD 2 ∴AB 2= 41(AC 2+BD 2) ∴ AC 2+BD 2=4AB 2 [henceproved] Video Explanation Was this answer helpful? 0 0 Similar questions optimal sets number for hypertrophyWebMar 29, 2024 · Given: where AD BC To Prove:- AB2 + CD2 = BD2 + AC2 Proof: Since AC BD ADC = ADB = 90 Doing (1) (2) AB2 AC2 = (AD2 + BD2) (AD2 + CD2) AB2 AC2 = AD2 + BD2 AD2 CD2 AB2 AC2 = BD2 CD2 AB2 + CD2 = BD2 + AC2 Hence proved Next: Example 13 Important → Ask a doubt Chapter 6 Class 10 Triangles Serial order wise Examples optimal setting for treadmillWebJan 31, 2024 · Area of trapezium = 1/2 × (sum of parallel sides) × height Calculation: ABCD is a trapezium AD II BC, AB = 5 cm, BC = 11 cm, AD = 7 cm, DA is produced to a point F such that AF = 3 cm and BF perpendicular to DF. In triangle BFA, BF 2 = AB 2 - AF 2 BF 2 = 5 2 - 3 2 BF 2 = 16 cm BF = 4 cm Area of trapezium = 1/2 × (sum of parallel sides) × height portland or vital statisticsWebFeb 19, 2012 · In a trapezium ABCD , if AB ll CD , then (AC2 - BD2 )= (i) BC2 + AD2 - Maths - Quadrilaterals - 1790859 Meritnation.com Class-9 » Maths Quadrilaterals Anmol Jain, asked a question Subject: Maths, asked on 19/2/12 In a trapezium ABCD , if AB ll CD , then (AC 2 - BD 2 )=? (i) BC 2 + AD 2 + 2BC x AD (ii) AB 2 + CD 2 + 2AB x BC portland or visitor information center